| VOLUME 11 | JANUARY 2010 | FREE |
By Terry Downs
| DISCLAIMER: This is not a primer on how to discharge capacitors or how to work on tube amplifiers safely. Do not work on high voltage products unless you are properly trained to do so. |
When my fascination for electronics began (I think that was in the crib), I played with a lot of tube equipment. My first job was working in a television repair shop at the age of 14. A television picture tube can hold a charge for a long time. The standard anode voltage was about 25,000 volts. What business does a 14 year old kid have messing around with that kind of hazard? Needless to say, I've been drawing sparks with a screwdriver for a long time.
Guitarists love tube amplifiers, and so do I. The capacitors in tube amplifiers can hold a dangerous charge. Some drain their charge fairly quick, and some take longer. Before you work on one, you really need to get those capacitors discharged. There are a few ways to accomplish this.
There is no doubt a discharge resistor is the right approach to limit the instantaneous current in the capacitor. The challenge is what resistance and wattage to choose. The resistance is easy. Here is the equation for the voltage across a capacitor when a discharge resistor is placed on it.
Where:
E = the initial voltage on the capacitor
e = the base of natural logarithms 2.71828
t = time is seconds
= tau or R x C
Vc = The voltage on the capacitor after t seconds
Of course, this equation is theoretical based on an ideal capacitor. In reality, a capacitor has leakage and will discharge faster on its own leakage current to various extents.
Being conservative let's determine a worst case discharge capacitance and voltage. A very standard example is the (2) 70µF capacitors in series in a Fender Twin Reverb. This is 35µF total. Other capacitors are also tied to this node through an inductor and various resistors. Let's say the largest amount of capacitance that would practically need to be discharged is 100µF, and the largest voltage is 500V. Let's calculate the voltage in the capacitor will be when discharged through a 200 ohm resistor after 1/10 second.
That's really nice. It would be practically zero after 1 second.
Now let's determine the power rating. Let's see what the instantaneous power is in a 200 ohm resistor.
Of course the current power will rapidly go to zero, but realistically there is not a good way to determine the wattage since we don't know how fast the inside of the resistor can heat up. One common discharge resistor I have seen is 150 ohm 10 watt. But, how do I know I'm not damaging the resistor every time I discharge it?
There are companies who make resistors that have an energy rating. It is easy to calculate the energy in a capacitor. We can forget about power.
Where:
Wc = Energy in Joules
C = Capacitance
E = Voltage
The energy of 100µF capacitor at 500V is,
The Ohmite Corporation has a nice selection of energy rated resistors. The 30 series are leaded wirewound components are axial lead parts.
Let's consider how to package the discharge probe. Some discharge resistor applications simply connect a resistor with wires on both ends, and use heat shrink tubing to insulate the resistor in the middle. The issue with that is, the high voltage is on one wire all the way down to the resistor. If the insulation becomes defective, it could become unsafe. The ultimate would be a probe tip in which a resistor can fit inside. Most voltmeter probes are too small for a resistor like we are considering. Some folks have used a ball point pen body for such an application. The largest diameter ballpoint pen I could easily find was the Wide-Body Bic offering.

I performed a HIPOT test of the pen body at 1,500 volts and there was no measureable current. Use this pen or any other at your own risk. I can't guarantee that next months lot of Bic pens will not have some impurities or chemical changes that will degrade its dielectric strength.
The 10 watt series 30 offering is too large in diameter at 0.406". However, the 5 watt series fits nicely. The largest resistance value on the 5 watt series is 75 ohms. At 75 ohms, the initial current is 6.66A. Since the fusing current is 5.55A, I'm not comfortable with this choice. Putting (2) 75 ohm resistors in series will fix that problem.
Resistance: 150 ohm (Ohmite 35J75R)
Initial Current: 3.33A (fusing current of resistor is 5.55A)
Energy: 12.5 joules (resistors are 18.77J x 2 = 37.54J)
Discharge Voltage: 0.636V in 0.1 seconds
Disassemble the pen from the clip side only as shown. Discard the encircled parts.

Click on picture for a higher resolution image
I used a 6D finishing nail for the probe tip. It was a perfect diameter for the hole in the pen. I was quite surprised I could solder to a nail. I cut the head off and chucked it up in a drill press. I used a file while the bit was rotating to round the tip off and remove the sharp end.

Click on picture for a higher resolution image
The distance from the resistor body to the probe end of the pen is ~1.7". I made the distance from the end of the probe to the resistor body ~2". The resistors and wire must be connected very close to fit the length of the pen body. I used a Pomona 565-AL-B-24-0 clip lead with one clip removed. Don't forget to thread the wire through the clip part of the pen before soldering the wire to the resistor. I also put a generous amount of clear silicone sealant (RTV) around the nail probe where the solder joint is located just prior to insertion. This should help to hold the probe in place against any axial force exerted by the probe tip.
Here's the finished probe.

Click on picture for a higher resolution image
If you use P-Touch software for a Brother label printer, I linked the label here.
These parts are available at Mouser.
Ohmite 35J75R Wirewound Resistor - Mouser
Web Page Link
Pomona 565-AL-B-24-0 Clip Lead Mouser
Web Page Link
On a final note, it should be noted that capacitors will have some energy in them after they have been discharged. Many capacitors have a "memory". If they were previously charged, they like to remain charged. This is called dielectric absorption. It's a good idea to connect a dead short clip lead across the capacitor after discharging them with a resistive probe.
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©2010 Terry Downs Music